y+y^2+2y+8=0

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Solution for y+y^2+2y+8=0 equation: 



y+y^2+2y+8=0

We add all the numbers together, and all the variables

y^2+3y+8=0

a = 1; b = 3; c = +8;
Δ = b2-4ac
Δ = 32-4·1·8
Δ = -23
Delta is less than zero, so there is no solution for the equation

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